Reverse bits of a given 32 bits unsigned integer.
For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as00111001011110000010100101000000).
Follow up:
If this function is called many times, how would you optimize it?Related problem:
Credits:
Special thanks to for adding this problem and creating all test cases.
遍历输入数的位,输出数反向添加,循环时候需要注意先移位后修改,反过来会错的。
#includeusing namespace std;class Solution {public: uint32_t reverseBits(uint32_t n) { uint32_t m=0; for(int i=0;i<32;i++){ m<<=1; m = m|(n & 1); n>>=1; } return m; }};int main(){ uint32_t n = 1; Solution sol; cout< <